-(-120-7x)+(40+2x)=2+(200+2x)

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Solution for -(-120-7x)+(40+2x)=2+(200+2x) equation: 



-(-120-7x)+(40+2x)=2+(200+2x)

We move all terms to the left:

-(-120-7x)+(40+2x)-(2+(200+2x))=0

We add all the numbers together, and all the variables

-(-7x-120)+(2x+40)-(2+(2x+200))=0

We get rid of parentheses

7x+2x-(2+(2x+200))+120+40=0



We calculate terms in parentheses: -(2+(2x+200)), so:

2+(2x+200)

determiningTheFunctionDomain
(2x+200)+2

We get rid of parentheses

2x+200+2

We add all the numbers together, and all the variables

2x+202

Back to the equation:

-(2x+202)



We add all the numbers together, and all the variables

9x-(2x+202)+160=0

We get rid of parentheses

9x-2x-202+160=0

We add all the numbers together, and all the variables

7x-42=0

We move all terms containing x to the left, all other terms to the right

7x=42

x=42/7

x=6

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