-(-2q-3)-3q=-4-5(q+2)

Solution for -(-2q-3)-3q=-4-5(q+2) equation:

-(-2q-3)-3q=-4-5(q+2)

We move all terms to the left:

-(-2q-3)-3q-(-4-5(q+2))=0

We add all the numbers together, and all the variables

-3q-(-2q-3)-(-4-5(q+2))=0

We get rid of parentheses

-3q+2q-(-4-5(q+2))+3=0


We calculate terms in parentheses: -(-4-5(q+2)), so:

-4-5(q+2)

determiningTheFunctionDomain
-5(q+2)-4

We multiply parentheses

-5q-10-4

We add all the numbers together, and all the variables

-5q-14

Back to the equation:

-(-5q-14)


We add all the numbers together, and all the variables

-1q-(-5q-14)+3=0

We get rid of parentheses

-1q+5q+14+3=0

We add all the numbers together, and all the variables

4q+17=0

We move all terms containing q to the left, all other terms to the right

4q=-17

q=-17/4

q=-4+1/4