-(-3-3d)=3(-3+2d)

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Solution for -(-3-3d)=3(-3+2d) equation: 



-(-3-3d)=3(-3+2d)

We move all terms to the left:

-(-3-3d)-(3(-3+2d))=0

We add all the numbers together, and all the variables

-(-3d-3)-(3(2d-3))=0

We get rid of parentheses

3d-(3(2d-3))+3=0



We calculate terms in parentheses: -(3(2d-3)), so:

3(2d-3)

We multiply parentheses

6d-9

Back to the equation:

-(6d-9)



We get rid of parentheses

3d-6d+9+3=0

We add all the numbers together, and all the variables

-3d+12=0

We move all terms containing d to the left, all other terms to the right

-3d=-12

d=-12/-3

d=+4

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