-(-3-q)=-1/2(6q-26

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Solution for -(-3-q)=-1/2(6q-26 equation:



-(-3-q)=-1/2(6q-26
We move all terms to the left:
-(-3-q)-(-1/2(6q-26)=0
Domain of the equation: 2(6q-26)!=0
q∈R
We add all the numbers together, and all the variables
-(-1q-3)-(-1/2(6q-26)=0
We get rid of parentheses
1q-(-1/2(6q-26)+3=0
We multiply all the terms by the denominator
1q*2(6q-26)+3-(-1=0
We add all the numbers together, and all the variables
1q*2(6q-26)=0
Wy multiply elements
2q^2(6=0

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