-(-3x-4)+7=6(8x-10)-12

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Solution for -(-3x-4)+7=6(8x-10)-12 equation: 



-(-3x-4)+7=6(8x-10)-12

We move all terms to the left:

-(-3x-4)+7-(6(8x-10)-12)=0

We get rid of parentheses

3x-(6(8x-10)-12)+4+7=0



We calculate terms in parentheses: -(6(8x-10)-12), so:

6(8x-10)-12

We multiply parentheses

48x-60-12

We add all the numbers together, and all the variables

48x-72

Back to the equation:

-(48x-72)



We add all the numbers together, and all the variables

3x-(48x-72)+11=0

We get rid of parentheses

3x-48x+72+11=0

We add all the numbers together, and all the variables

-45x+83=0

We move all terms containing x to the left, all other terms to the right

-45x=-83

x=-83/-45

x=1+38/45

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