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-(-4x+20)2x=28
We move all terms to the left:
-(-4x+20)2x-(28)=0
We multiply parentheses
8x^2-40x-28=0
a = 8; b = -40; c = -28;
Δ = b2-4ac
Δ = -402-4·8·(-28)
Δ = 2496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2496}=\sqrt{64*39}=\sqrt{64}*\sqrt{39}=8\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-8\sqrt{39}}{2*8}=\frac{40-8\sqrt{39}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+8\sqrt{39}}{2*8}=\frac{40+8\sqrt{39}}{16} $
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