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-(-4x-1)-6/5x=4/5x-1
We move all terms to the left:
-(-4x-1)-6/5x-(4/5x-1)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5x-1)!=0We get rid of parentheses
x∈R
4x-6/5x-4/5x+1+1=0
We multiply all the terms by the denominator
4x*5x+1*5x+1*5x-6-4=0
We add all the numbers together, and all the variables
4x*5x+1*5x+1*5x-10=0
Wy multiply elements
20x^2+5x+5x-10=0
We add all the numbers together, and all the variables
20x^2+10x-10=0
a = 20; b = 10; c = -10;
Δ = b2-4ac
Δ = 102-4·20·(-10)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-30}{2*20}=\frac{-40}{40} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+30}{2*20}=\frac{20}{40} =1/2 $
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