-(-8x+4)12x=-4(x-7)+6x

Solution for -(-8x+4)12x=-4(x-7)+6x equation:

-(-8x+4)12x=-4(x-7)+6x

We move all terms to the left:

-(-8x+4)12x-(-4(x-7)+6x)=0

We multiply parentheses

96x^2-48x-(-4(x-7)+6x)=0


We calculate terms in parentheses: -(-4(x-7)+6x), so:

-4(x-7)+6x

We add all the numbers together, and all the variables

6x-4(x-7)

We multiply parentheses

6x-4x+28

We add all the numbers together, and all the variables

2x+28

Back to the equation:

-(2x+28)


We get rid of parentheses

96x^2-48x-2x-28=0

We add all the numbers together, and all the variables

96x^2-50x-28=0

a = 96; b = -50; c = -28;
Δ = b2-4ac
Δ = -502-4·96·(-28)
Δ = 13252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13252}=\sqrt{4*3313}=\sqrt{4}*\sqrt{3313}=2\sqrt{3313}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{3313}}{2*96}=\frac{50-2\sqrt{3313}}{192}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{3313}}{2*96}=\frac{50+2\sqrt{3313}}{192}
$