-(-w+6)(-w+3)=0

Solution for -(-w+6)(-w+3)=0 equation:

-(-w+6)(-w+3)=0

We add all the numbers together, and all the variables

-(-1w+6)(-1w+3)=0

We multiply parentheses ..

-(+w^2-3w-6w+18)=0

We get rid of parentheses

-w^2+3w+6w-18=0

We add all the numbers together, and all the variables

-1w^2+9w-18=0

a = -1; b = 9; c = -18;
Δ = b2-4ac
Δ = 92-4·(-1)·(-18)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3}{2*-1}=\frac{-12}{-2}
=+6
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3}{2*-1}=\frac{-6}{-2}
=+3
$