-(-x-8)+4x=2(x+4)+x

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Solution for -(-x-8)+4x=2(x+4)+x equation: 



-(-x-8)+4x=2(x+4)+x

We move all terms to the left:

-(-x-8)+4x-(2(x+4)+x)=0

We add all the numbers together, and all the variables

-(-1x-8)+4x-(2(x+4)+x)=0

We add all the numbers together, and all the variables

4x-(-1x-8)-(2(x+4)+x)=0

We get rid of parentheses

4x+1x-(2(x+4)+x)+8=0



We calculate terms in parentheses: -(2(x+4)+x), so:

2(x+4)+x

We add all the numbers together, and all the variables

x+2(x+4)

We multiply parentheses

x+2x+8

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

5x-(3x+8)+8=0

We get rid of parentheses

5x-3x-8+8=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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