-(1)/(2)c-5=(1)/(2)c

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Solution for -(1)/(2)c-5=(1)/(2)c equation: 



-(1)/(2)c-5=(1)/(2)c

We move all terms to the left:

-(1)/(2)c-5-((1)/(2)c)=0



Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R





Domain of the equation: 2c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

-1/2c-(+1/2c)-5=0

We get rid of parentheses

-1/2c-1/2c-5=0

We multiply all the terms by the denominator


-5*2c-1-1=0

We add all the numbers together, and all the variables

-5*2c-2=0

Wy multiply elements

-10c-2=0

We move all terms containing c to the left, all other terms to the right

-10c=2

c=2/-10

c=-1/5

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