-(1)/(9)(x-27)+(1)/(3)(x)+3)=x+67

Solution for -(1)/(9)(x-27)+(1)/(3)(x)+3)=x+67 equation:

-(1)/(9)(x-27)+(1)/(3)(x)+3)=x+67

We move all terms to the left:

-(1)/(9)(x-27)+(1)/(3)(x)+3)-(x+67)=0


Domain of the equation: 9(x-27)!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

-1/9(x-27)+1/3x+3)-(x=0

We calculate fractions


3)-(x+(-3x)/(27x^2-729x)+(9xx/(27x^2-729x)=0


We calculate terms in parentheses: +(9xx/(27x^2-729x), so:

9xx/(27x^2-729x

We multiply all the terms by the denominator


9xx

Back to the equation:

+(9xx)


We multiply all the terms by the denominator


-x*(27x^2-729x)+(-3x)+9xx*(27x^2-729x)+3=0

We multiply parentheses

-27x^3+729x^2+243x^3-6561x^2+(-3x)+3=0

We get rid of parentheses

-27x^3+729x^2+243x^3-6561x^2-3x+3=0

We do not support expression: x^3