-(1+4b)+5=2(b+2)-6b

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Solution for -(1+4b)+5=2(b+2)-6b equation: 



-(1+4b)+5=2(b+2)-6b

We move all terms to the left:

-(1+4b)+5-(2(b+2)-6b)=0

We add all the numbers together, and all the variables

-(4b+1)-(2(b+2)-6b)+5=0

We get rid of parentheses

-4b-(2(b+2)-6b)-1+5=0



We calculate terms in parentheses: -(2(b+2)-6b), so:

2(b+2)-6b

We add all the numbers together, and all the variables

-6b+2(b+2)

We multiply parentheses

-6b+2b+4

We add all the numbers together, and all the variables

-4b+4

Back to the equation:

-(-4b+4)



We add all the numbers together, and all the variables

-4b-(-4b+4)+4=0

We get rid of parentheses

-4b+4b-4+4=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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