-(1+8x)-7x=(6x-4)

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Solution for -(1+8x)-7x=(6x-4) equation: 



-(1+8x)-7x=(6x-4)

We move all terms to the left:

-(1+8x)-7x-((6x-4))=0

We add all the numbers together, and all the variables

-(8x+1)-7x-((6x-4))=0

We add all the numbers together, and all the variables

-7x-(8x+1)-((6x-4))=0

We get rid of parentheses

-7x-8x-((6x-4))-1=0



We calculate terms in parentheses: -((6x-4)), so:

(6x-4)

We get rid of parentheses

6x-4

Back to the equation:

-(6x-4)



We add all the numbers together, and all the variables

-15x-(6x-4)-1=0

We get rid of parentheses

-15x-6x+4-1=0

We add all the numbers together, and all the variables

-21x+3=0

We move all terms containing x to the left, all other terms to the right

-21x=-3

x=-3/-21

x=1/7

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