-(1+n)-n=-(3n-2)

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Solution for -(1+n)-n=-(3n-2) equation: 



-(1+n)-n=-(3n-2)

We move all terms to the left:

-(1+n)-n-(-(3n-2))=0

We add all the numbers together, and all the variables

-(n+1)-n-(-(3n-2))=0

We add all the numbers together, and all the variables

-1n-(n+1)-(-(3n-2))=0

We get rid of parentheses

-1n-n-(-(3n-2))-1=0



We calculate terms in parentheses: -(-(3n-2)), so:

-(3n-2)

We get rid of parentheses

-3n+2

Back to the equation:

-(-3n+2)



We add all the numbers together, and all the variables

-2n-(-3n+2)-1=0

We get rid of parentheses

-2n+3n-2-1=0

We add all the numbers together, and all the variables

n-3=0

We move all terms containing n to the left, all other terms to the right

n=3

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