-(1-6n)=3(2n-4)+11

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Solution for -(1-6n)=3(2n-4)+11 equation: 



-(1-6n)=3(2n-4)+11

We move all terms to the left:

-(1-6n)-(3(2n-4)+11)=0

We add all the numbers together, and all the variables

-(-6n+1)-(3(2n-4)+11)=0

We get rid of parentheses

6n-(3(2n-4)+11)-1=0



We calculate terms in parentheses: -(3(2n-4)+11), so:

3(2n-4)+11

We multiply parentheses

6n-12+11

We add all the numbers together, and all the variables

6n-1

Back to the equation:

-(6n-1)



We get rid of parentheses

6n-6n+1-1=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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