-(1/2)x-(3/5)=(1/5)x

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Solution for -(1/2)x-(3/5)=(1/5)x equation: 



-(1/2)x-(3/5)=(1/5)x

We move all terms to the left:

-(1/2)x-(3/5)-((1/5)x)=0



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 5)x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(+1/2)x-((+1/5)x)-(+3/5)=0

We multiply parentheses

-x^2-((+1/5)x)-(+3/5)=0

We get rid of parentheses

-x^2-((+1/5)x)-3/5=0

We calculate fractions


-x^2=0

We add all the numbers together, and all the variables

-1x^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-2}=0$

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