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(x+1)/2 = (x+3)/x;x
x
69;5
43.4;7
26;5
25;4
| 6x-1=2.5 | | 5y-8=27-3y | | 12y^2-15y= | | Sin(12)=cos(x) | | 25=3n-8 | | 6d-3=d+12 | | 12a-b=8 | | 3x^2=35-8x | | 4e+8=40 | | 7+w=6 | | 16+17x=28+13x | | -6x+9=4x+3 | | 8(q+2)-25= | | 12x^2+46x+15=0 | | 2(3n-5)=32 | | tan=1.1 | | -0.4=x-0.9 | | https://www.vle.mathswatch.com/images/questions/question347.png | | 4(x+28)-3(-x+7)=28 | | 3(x+8)=x+10 | | X-7.3=-4.1 | | 3v=16+5v | | -12-9x=-14-7x | | 2m-5n=265 | | 9x-8=x-24 | | (6x-12)/6=24 | | 4y-3/5=y-2 | | 6x^2-18x-6=0 | | -10=15x | | -6x+5-3(x-1)=-(5x-4)-3+3 | | 9p+5q=43 | | 6-x=y |
