-(1/2x-5)=2x-10

Solution for -(1/2x-5)=2x-10 equation:

-(1/2x-5)=2x-10

We move all terms to the left:

-(1/2x-5)-(2x-10)=0


Domain of the equation: 2x-5)!=0

x∈R


We get rid of parentheses

-1/2x-2x+5+10=0

We multiply all the terms by the denominator


-2x*2x+5*2x+10*2x-1=0

Wy multiply elements

-4x^2+10x+20x-1=0

We add all the numbers together, and all the variables

-4x^2+30x-1=0

a = -4; b = 30; c = -1;
Δ = b2-4ac
Δ = 302-4·(-4)·(-1)
Δ = 884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{884}=\sqrt{4*221}=\sqrt{4}*\sqrt{221}=2\sqrt{221}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{221}}{2*-4}=\frac{-30-2\sqrt{221}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{221}}{2*-4}=\frac{-30+2\sqrt{221}}{-8}
$