-(1/3)(9c-36)=-9

Solution for -(1/3)(9c-36)=-9 equation:

-(1/3)(9c-36)=-9

We move all terms to the left:

-(1/3)(9c-36)-(-9)=0


Domain of the equation: 3)(9c-36)!=0

c∈R


We add all the numbers together, and all the variables

-(+1/3)(9c-36)-(-9)=0

We add all the numbers together, and all the variables

-(+1/3)(9c-36)+9=0

We multiply parentheses ..

-(+9c^2+1/3*-36)+9=0

We multiply all the terms by the denominator


-(+9c^2+1+9*3*-36)=0

We get rid of parentheses

-9c^2-1+36-9*3*=0

We add all the numbers together, and all the variables

-9c^2=0

a = -9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-9)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{-18}=0$