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-(1/3)(x-5)(x+5)=0
Domain of the equation: 3)(x-5)(x+5)!=0We add all the numbers together, and all the variables
x∈R
-(+1/3)(x-5)(x+5)=0
We multiply parentheses ..
-(+x^2+1/3*-5)(x+5)=0
We multiply all the terms by the denominator
-(+x^2+1=0
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