-(1/6)(x-12)+(1-3)(x+3)=x-2

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Solution for -(1/6)(x-12)+(1-3)(x+3)=x-2 equation: 


x in (-oo:+oo)

(1-3)*(x+3)-((1/6)*(x-12)) = x-2 // - x-2

(1-3)*(x+3)-((1/6)*(x-12))-x+2 = 0

(-1/6)*(x-12)+(1-3)*(x+3)-x+2 = 0

2-1/6*(x-12)-2*(x+3)-x = 0

2-1/6*(x-12)-2*(x+3)-x = 0

2-13/6*x-x-4 = 0

2-19/6*x-4 = 0

-19/6*x-2 = 0

-19/6*x-2 = 0

-19/6*x-2 = 0 // + 2

-19/6*x = 2 // : -19/6

x = 2/(-19/6)

x = -12/19

x = -12/19

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