-(1/6)(x-18)+(1/3)(x+3)=x+4

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Solution for -(1/6)(x-18)+(1/3)(x+3)=x+4 equation: 


x in (-oo:+oo)

(1/3)*(x+3)-((1/6)*(x-18)) = x+4 // - x+4

(1/3)*(x+3)-((1/6)*(x-18))-x-4 = 0

(-1/6)*(x-18)+(1/3)*(x+3)-x-4 = 0

1/3*(x+3)-1/6*(x-18)-x-4 = 0

1/3*(x+3)-1/6*(x-18)-x-4 = 0

1/6*x-x-4+4 = 0

4-5/6*x-4 = 0

-5/6*x = 0

(-5*x)/6 = 0

(-5*x)/6 = 0 // * 6

-5*x = 0

-5*x = 0 // : -5

x = 0

x = 0

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