-(1/9)(x-18)+(1/3)(x+3)=x-4

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Solution for -(1/9)(x-18)+(1/3)(x+3)=x-4 equation:



-(1/9)(x-18)+(1/3)(x+3)=x-4
We move all terms to the left:
-(1/9)(x-18)+(1/3)(x+3)-(x-4)=0
Domain of the equation: 9)(x-18)!=0
x∈R
Domain of the equation: 3)(x+3)!=0
x∈R
We add all the numbers together, and all the variables
-(+1/9)(x-18)+(+1/3)(x+3)-(x-4)=0
We get rid of parentheses
-(+1/9)(x-18)+(+1/3)(x+3)-x+4=0
We multiply parentheses ..
-(+x^2+1/9*-18)+(+1/3)(x+3)-x+4=0
We calculate fractions
There is no solution for this equation

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