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-(1/9)b=-12
We move all terms to the left:
-(1/9)b-(-12)=0
Domain of the equation: 9)b!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
-(+1/9)b-(-12)=0
We add all the numbers together, and all the variables
-(+1/9)b+12=0
We multiply parentheses
-b^2+12=0
We add all the numbers together, and all the variables
-1b^2+12=0
a = -1; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-1)·12
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*-1}=\frac{0-4\sqrt{3}}{-2} =-\frac{4\sqrt{3}}{-2} =-\frac{2\sqrt{3}}{-1} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*-1}=\frac{0+4\sqrt{3}}{-2} =\frac{4\sqrt{3}}{-2} =\frac{2\sqrt{3}}{-1} $
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