-(10-k)=3(k+4)

Solution for -(10-k)=3(k+4) equation:

-(10-k)=3(k+4)

We move all terms to the left:

-(10-k)-(3(k+4))=0

We add all the numbers together, and all the variables

-(-1k+10)-(3(k+4))=0

We get rid of parentheses

1k-(3(k+4))-10=0


We calculate terms in parentheses: -(3(k+4)), so:

3(k+4)

We multiply parentheses

3k+12

Back to the equation:

-(3k+12)


We add all the numbers together, and all the variables

k-(3k+12)-10=0

We get rid of parentheses

k-3k-12-10=0

We add all the numbers together, and all the variables

-2k-22=0

We move all terms containing k to the left, all other terms to the right

-2k=22

k=22/-2

k=-11