-(10x-(3x+8))=-3-(4(3x-4)-3x)

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Solution for -(10x-(3x+8))=-3-(4(3x-4)-3x) equation:



-(10x-(3x+8))=-3-(4(3x-4)-3x)
We move all terms to the left:
-(10x-(3x+8))-(-3-(4(3x-4)-3x))=0
We calculate terms in parentheses: -(10x-(3x+8)), so:
10x-(3x+8)
We get rid of parentheses
10x-3x-8
We add all the numbers together, and all the variables
7x-8
Back to the equation:
-(7x-8)
We calculate terms in parentheses: -(-3-(4(3x-4)-3x)), so:
-3-(4(3x-4)-3x)
determiningTheFunctionDomain -(4(3x-4)-3x)-3
We calculate terms in parentheses: -(4(3x-4)-3x), so:
4(3x-4)-3x
We add all the numbers together, and all the variables
-3x+4(3x-4)
We multiply parentheses
-3x+12x-16
We add all the numbers together, and all the variables
9x-16
Back to the equation:
-(9x-16)
We get rid of parentheses
-9x+16-3
We add all the numbers together, and all the variables
-9x+13
Back to the equation:
-(-9x+13)
We get rid of parentheses
-7x+9x+8-13=0
We add all the numbers together, and all the variables
2x-5=0
We move all terms containing x to the left, all other terms to the right
2x=5
x=5/2
x=2+1/2

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