-(10x-18)+19(4+3x)=9-21(x+7)+4(18-3x)

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Solution for -(10x-18)+19(4+3x)=9-21(x+7)+4(18-3x) equation: 



-(10x-18)+19(4+3x)=9-21(x+7)+4(18-3x)

We move all terms to the left:

-(10x-18)+19(4+3x)-(9-21(x+7)+4(18-3x))=0

We add all the numbers together, and all the variables

-(10x-18)+19(3x+4)-(9-21(x+7)+4(-3x+18))=0

We multiply parentheses

-(10x-18)+57x-(9-21(x+7)+4(-3x+18))+76=0

We get rid of parentheses

-10x+57x-(9-21(x+7)+4(-3x+18))+18+76=0



We calculate terms in parentheses: -(9-21(x+7)+4(-3x+18)), so:

9-21(x+7)+4(-3x+18)

determiningTheFunctionDomain
-21(x+7)+4(-3x+18)+9

We multiply parentheses

-21x-12x-147+72+9

We add all the numbers together, and all the variables

-33x-66

Back to the equation:

-(-33x-66)



We add all the numbers together, and all the variables

47x-(-33x-66)+94=0

We get rid of parentheses

47x+33x+66+94=0

We add all the numbers together, and all the variables

80x+160=0

We move all terms containing x to the left, all other terms to the right

80x=-160

x=-160/80

x=-2

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