-(10x-4)-(4x-5)+6=-4(x-1)-(14x+4)+3

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Solution for -(10x-4)-(4x-5)+6=-4(x-1)-(14x+4)+3 equation: 



-(10x-4)-(4x-5)+6=-4(x-1)-(14x+4)+3

We move all terms to the left:

-(10x-4)-(4x-5)+6-(-4(x-1)-(14x+4)+3)=0

We get rid of parentheses

-10x-4x-(-4(x-1)-(14x+4)+3)+4+5+6=0



We calculate terms in parentheses: -(-4(x-1)-(14x+4)+3), so:

-4(x-1)-(14x+4)+3

We multiply parentheses

-4x-(14x+4)+4+3

We get rid of parentheses

-4x-14x-4+4+3

We add all the numbers together, and all the variables

-18x+3

Back to the equation:

-(-18x+3)



We add all the numbers together, and all the variables

-14x-(-18x+3)+15=0

We get rid of parentheses

-14x+18x-3+15=0

We add all the numbers together, and all the variables

4x+12=0

We move all terms containing x to the left, all other terms to the right

4x=-12

x=-12/4

x=-3

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