-(10y-3)=12(y+2)

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Solution for -(10y-3)=12(y+2) equation: 



-(10y-3)=12(y+2)

We move all terms to the left:

-(10y-3)-(12(y+2))=0

We get rid of parentheses

-10y-(12(y+2))+3=0



We calculate terms in parentheses: -(12(y+2)), so:

12(y+2)

We multiply parentheses

12y+24

Back to the equation:

-(12y+24)



We get rid of parentheses

-10y-12y-24+3=0

We add all the numbers together, and all the variables

-22y-21=0

We move all terms containing y to the left, all other terms to the right

-22y=21

y=21/-22

y=-21/22

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