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-(11x-3)-(3x-5)+7=-6(x-1)-(12x+6)+3
We move all terms to the left:
-(11x-3)-(3x-5)+7-(-6(x-1)-(12x+6)+3)=0
We get rid of parentheses
-11x-3x-(-6(x-1)-(12x+6)+3)+3+5+7=0
We calculate terms in parentheses: -(-6(x-1)-(12x+6)+3), so:We add all the numbers together, and all the variables
-6(x-1)-(12x+6)+3
We multiply parentheses
-6x-(12x+6)+6+3
We get rid of parentheses
-6x-12x-6+6+3
We add all the numbers together, and all the variables
-18x+3
Back to the equation:
-(-18x+3)
-14x-(-18x+3)+15=0
We get rid of parentheses
-14x+18x-3+15=0
We add all the numbers together, and all the variables
4x+12=0
We move all terms containing x to the left, all other terms to the right
4x=-12
x=-12/4
x=-3
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