-(11x-3)=7(2x+x+5)

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Solution for -(11x-3)=7(2x+x+5) equation: 



-(11x-3)=7(2x+x+5)

We move all terms to the left:

-(11x-3)-(7(2x+x+5))=0

We add all the numbers together, and all the variables

-(11x-3)-(7(3x+5))=0

We get rid of parentheses

-11x-(7(3x+5))+3=0



We calculate terms in parentheses: -(7(3x+5)), so:

7(3x+5)

We multiply parentheses

21x+35

Back to the equation:

-(21x+35)



We get rid of parentheses

-11x-21x-35+3=0

We add all the numbers together, and all the variables

-32x-32=0

We move all terms containing x to the left, all other terms to the right

-32x=32

x=32/-32

x=-1

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