-(11x-4)-(3x-5)+6=-8(x-1)-(9x+8)+3

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Solution for -(11x-4)-(3x-5)+6=-8(x-1)-(9x+8)+3 equation: 



-(11x-4)-(3x-5)+6=-8(x-1)-(9x+8)+3

We move all terms to the left:

-(11x-4)-(3x-5)+6-(-8(x-1)-(9x+8)+3)=0

We get rid of parentheses

-11x-3x-(-8(x-1)-(9x+8)+3)+4+5+6=0



We calculate terms in parentheses: -(-8(x-1)-(9x+8)+3), so:

-8(x-1)-(9x+8)+3

We multiply parentheses

-8x-(9x+8)+8+3

We get rid of parentheses

-8x-9x-8+8+3

We add all the numbers together, and all the variables

-17x+3

Back to the equation:

-(-17x+3)



We add all the numbers together, and all the variables

-14x-(-17x+3)+15=0

We get rid of parentheses

-14x+17x-3+15=0

We add all the numbers together, and all the variables

3x+12=0

We move all terms containing x to the left, all other terms to the right

3x=-12

x=-12/3

x=-4

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