-(12v+2)+11=-8(v-9)-11v

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Solution for -(12v+2)+11=-8(v-9)-11v equation: 



-(12v+2)+11=-8(v-9)-11v

We move all terms to the left:

-(12v+2)+11-(-8(v-9)-11v)=0

We get rid of parentheses

-12v-(-8(v-9)-11v)-2+11=0



We calculate terms in parentheses: -(-8(v-9)-11v), so:

-8(v-9)-11v

We add all the numbers together, and all the variables

-11v-8(v-9)

We multiply parentheses

-11v-8v+72

We add all the numbers together, and all the variables

-19v+72

Back to the equation:

-(-19v+72)



We add all the numbers together, and all the variables

-12v-(-19v+72)+9=0

We get rid of parentheses

-12v+19v-72+9=0

We add all the numbers together, and all the variables

7v-63=0

We move all terms containing v to the left, all other terms to the right

7v=63

v=63/7

v=9

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