-(12x-4)-(2x-5)+6=-3(x-1)-(14x+3)+3

Solution for -(12x-4)-(2x-5)+6=-3(x-1)-(14x+3)+3 equation:

-(12x-4)-(2x-5)+6=-3(x-1)-(14x+3)+3

We move all terms to the left:

-(12x-4)-(2x-5)+6-(-3(x-1)-(14x+3)+3)=0

We get rid of parentheses

-12x-2x-(-3(x-1)-(14x+3)+3)+4+5+6=0


We calculate terms in parentheses: -(-3(x-1)-(14x+3)+3), so:

-3(x-1)-(14x+3)+3

We multiply parentheses

-3x-(14x+3)+3+3

We get rid of parentheses

-3x-14x-3+3+3

We add all the numbers together, and all the variables

-17x+3

Back to the equation:

-(-17x+3)


We add all the numbers together, and all the variables

-14x-(-17x+3)+15=0

We get rid of parentheses

-14x+17x-3+15=0

We add all the numbers together, and all the variables

3x+12=0

We move all terms containing x to the left, all other terms to the right

3x=-12

x=-12/3

x=-4