-(13/5)y=-26

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Solution for -(13/5)y=-26 equation:



-(13/5)y=-26
We move all terms to the left:
-(13/5)y-(-26)=0
Domain of the equation: 5)y!=0
y!=0/1
y!=0
y∈R
We add all the numbers together, and all the variables
-(+13/5)y-(-26)=0
We add all the numbers together, and all the variables
-(+13/5)y+26=0
We multiply parentheses
-13y^2+26=0
a = -13; b = 0; c = +26;
Δ = b2-4ac
Δ = 02-4·(-13)·26
Δ = 1352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1352}=\sqrt{676*2}=\sqrt{676}*\sqrt{2}=26\sqrt{2}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-26\sqrt{2}}{2*-13}=\frac{0-26\sqrt{2}}{-26} =-\frac{26\sqrt{2}}{-26} =-\frac{\sqrt{2}}{-1} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+26\sqrt{2}}{2*-13}=\frac{0+26\sqrt{2}}{-26} =\frac{26\sqrt{2}}{-26} =\frac{\sqrt{2}}{-1} $

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