-(13k+2k)=3k+4(k-3)

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Solution for -(13k+2k)=3k+4(k-3) equation: 



-(13k+2k)=3k+4(k-3)

We move all terms to the left:

-(13k+2k)-(3k+4(k-3))=0

We add all the numbers together, and all the variables

-(+15k)-(3k+4(k-3))=0

We get rid of parentheses

-15k-(3k+4(k-3))=0



We calculate terms in parentheses: -(3k+4(k-3)), so:

3k+4(k-3)

We multiply parentheses

3k+4k-12

We add all the numbers together, and all the variables

7k-12

Back to the equation:

-(7k-12)



We get rid of parentheses

-15k-7k+12=0

We add all the numbers together, and all the variables

-22k+12=0

We move all terms containing k to the left, all other terms to the right

-22k=-12

k=-12/-22

k=6/11

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