-(13k+2k)=3k+4(k-3)

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Solution for -(13k+2k)=3k+4(k-3) equation:



-(13k+2k)=3k+4(k-3)
We move all terms to the left:
-(13k+2k)-(3k+4(k-3))=0
We add all the numbers together, and all the variables
-(+15k)-(3k+4(k-3))=0
We get rid of parentheses
-15k-(3k+4(k-3))=0
We calculate terms in parentheses: -(3k+4(k-3)), so:
3k+4(k-3)
We multiply parentheses
3k+4k-12
We add all the numbers together, and all the variables
7k-12
Back to the equation:
-(7k-12)
We get rid of parentheses
-15k-7k+12=0
We add all the numbers together, and all the variables
-22k+12=0
We move all terms containing k to the left, all other terms to the right
-22k=-12
k=-12/-22
k=6/11

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