-(15/7)n-(6/7)=-(10/7)

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Solution for -(15/7)n-(6/7)=-(10/7) equation: 



-(15/7)n-(6/7)=-(10/7)

We move all terms to the left:

-(15/7)n-(6/7)-(-(10/7))=0



Domain of the equation: 7)n!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

-(+15/7)n-(+6/7)-(-(+10/7))=0

We multiply parentheses

-15n^2-(+6/7)-(-(+10/7))=0

We get rid of parentheses

-15n^2-6/7-(-(+10/7))=0

We calculate fractions


-15n^2=0

a = -15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-15)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{-30}=0$

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