-(1y+8)-5=4(y+2)-6y

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Solution for -(1y+8)-5=4(y+2)-6y equation: 



-(1y+8)-5=4(y+2)-6y

We move all terms to the left:

-(1y+8)-5-(4(y+2)-6y)=0

We add all the numbers together, and all the variables

-(y+8)-(4(y+2)-6y)-5=0

We get rid of parentheses

-y-(4(y+2)-6y)-8-5=0



We calculate terms in parentheses: -(4(y+2)-6y), so:

4(y+2)-6y

We add all the numbers together, and all the variables

-6y+4(y+2)

We multiply parentheses

-6y+4y+8

We add all the numbers together, and all the variables

-2y+8

Back to the equation:

-(-2y+8)



We add all the numbers together, and all the variables

-1y-(-2y+8)-13=0

We get rid of parentheses

-1y+2y-8-13=0

We add all the numbers together, and all the variables

y-21=0

We move all terms containing y to the left, all other terms to the right

y=21

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