-(2+3r)+2=-6(r-1)

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Solution for -(2+3r)+2=-6(r-1) equation: 



-(2+3r)+2=-6(r-1)

We move all terms to the left:

-(2+3r)+2-(-6(r-1))=0

We add all the numbers together, and all the variables

-(3r+2)-(-6(r-1))+2=0

We get rid of parentheses

-3r-(-6(r-1))-2+2=0



We calculate terms in parentheses: -(-6(r-1)), so:

-6(r-1)

We multiply parentheses

-6r+6

Back to the equation:

-(-6r+6)



We add all the numbers together, and all the variables

-3r-(-6r+6)=0

We get rid of parentheses

-3r+6r-6=0

We add all the numbers together, and all the variables

3r-6=0

We move all terms containing r to the left, all other terms to the right

3r=6

r=6/3

r=2

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