-(2+5)+(6z+1)=-2(z+1)

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Solution for -(2+5)+(6z+1)=-2(z+1) equation:


Simplifying
-1(2 + 5) + (6z + 1) = -2(z + 1)

Combine like terms: 2 + 5 = 7
-1(7) + (6z + 1) = -2(z + 1)

Multiply -1 * 7
-7 + (6z + 1) = -2(z + 1)

Reorder the terms:
-7 + (1 + 6z) = -2(z + 1)

Remove parenthesis around (1 + 6z)
-7 + 1 + 6z = -2(z + 1)

Combine like terms: -7 + 1 = -6
-6 + 6z = -2(z + 1)

Reorder the terms:
-6 + 6z = -2(1 + z)
-6 + 6z = (1 * -2 + z * -2)
-6 + 6z = (-2 + -2z)

Solving
-6 + 6z = -2 + -2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2z' to each side of the equation.
-6 + 6z + 2z = -2 + -2z + 2z

Combine like terms: 6z + 2z = 8z
-6 + 8z = -2 + -2z + 2z

Combine like terms: -2z + 2z = 0
-6 + 8z = -2 + 0
-6 + 8z = -2

Add '6' to each side of the equation.
-6 + 6 + 8z = -2 + 6

Combine like terms: -6 + 6 = 0
0 + 8z = -2 + 6
8z = -2 + 6

Combine like terms: -2 + 6 = 4
8z = 4

Divide each side by '8'.
z = 0.5

Simplifying
z = 0.5

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