-(2+C)-(4+2c)=6

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Solution for -(2+C)-(4+2c)=6 equation:


Simplifying
-1(2 + C) + -1(4 + 2c) = 6
(2 * -1 + C * -1) + -1(4 + 2c) = 6
(-2 + -1C) + -1(4 + 2c) = 6
-2 + -1C + (4 * -1 + 2c * -1) = 6
-2 + -1C + (-4 + -2c) = 6

Reorder the terms:
-2 + -4 + -1C + -2c = 6

Combine like terms: -2 + -4 = -6
-6 + -1C + -2c = 6

Solving
-6 + -1C + -2c = 6

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + -1C + 6 + -2c = 6 + 6

Reorder the terms:
-6 + 6 + -1C + -2c = 6 + 6

Combine like terms: -6 + 6 = 0
0 + -1C + -2c = 6 + 6
-1C + -2c = 6 + 6

Combine like terms: 6 + 6 = 12
-1C + -2c = 12

Add '2c' to each side of the equation.
-1C + -2c + 2c = 12 + 2c

Combine like terms: -2c + 2c = 0
-1C + 0 = 12 + 2c
-1C = 12 + 2c

Divide each side by '-1'.
C = -12 + -2c

Simplifying
C = -12 + -2c

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