-(2-2y)=-2(3y-3)

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Solution for -(2-2y)=-2(3y-3) equation: 



-(2-2y)=-2(3y-3)

We move all terms to the left:

-(2-2y)-(-2(3y-3))=0

We add all the numbers together, and all the variables

-(-2y+2)-(-2(3y-3))=0

We get rid of parentheses

2y-(-2(3y-3))-2=0



We calculate terms in parentheses: -(-2(3y-3)), so:

-2(3y-3)

We multiply parentheses

-6y+6

Back to the equation:

-(-6y+6)



We get rid of parentheses

2y+6y-6-2=0

We add all the numbers together, and all the variables

8y-8=0

We move all terms containing y to the left, all other terms to the right

8y=8

y=8/8

y=1

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