-(2-3d)=5(d+2)

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Solution for -(2-3d)=5(d+2) equation: 



-(2-3d)=5(d+2)

We move all terms to the left:

-(2-3d)-(5(d+2))=0

We add all the numbers together, and all the variables

-(-3d+2)-(5(d+2))=0

We get rid of parentheses

3d-(5(d+2))-2=0



We calculate terms in parentheses: -(5(d+2)), so:

5(d+2)

We multiply parentheses

5d+10

Back to the equation:

-(5d+10)



We get rid of parentheses

3d-5d-10-2=0

We add all the numbers together, and all the variables

-2d-12=0

We move all terms containing d to the left, all other terms to the right

-2d=12

d=12/-2

d=-6

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