-(2-4x)-(3-4x)+4=-(-3+6x)+x+1

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Solution for -(2-4x)-(3-4x)+4=-(-3+6x)+x+1 equation: 



-(2-4x)-(3-4x)+4=-(-3+6x)+x+1

We move all terms to the left:

-(2-4x)-(3-4x)+4-(-(-3+6x)+x+1)=0

We add all the numbers together, and all the variables

-(-4x+2)-(-4x+3)-(-(6x-3)+x+1)+4=0

We get rid of parentheses

4x+4x-(-(6x-3)+x+1)-2-3+4=0



We calculate terms in parentheses: -(-(6x-3)+x+1), so:

-(6x-3)+x+1

We add all the numbers together, and all the variables

x-(6x-3)+1

We get rid of parentheses

x-6x+3+1

We add all the numbers together, and all the variables

-5x+4

Back to the equation:

-(-5x+4)



We add all the numbers together, and all the variables

8x-(-5x+4)-1=0

We get rid of parentheses

8x+5x-4-1=0

We add all the numbers together, and all the variables

13x-5=0

We move all terms containing x to the left, all other terms to the right

13x=5

x=5/13

x=5/13

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