-(2-i)(2-i)=

Solution for -(2-i)(2-i)= equation:

Simplifying
-1(2 + -1i)(2 + -1i) = 0

Multiply (2 + -1i) * (2 + -1i)
-1(2(2 + -1i) + -1i * (2 + -1i)) = 0
-1((2 * 2 + -1i * 2) + -1i * (2 + -1i)) = 0
-1((4 + -2i) + -1i * (2 + -1i)) = 0
-1(4 + -2i + (2 * -1i + -1i * -1i)) = 0
-1(4 + -2i + (-2i + 1i2)) = 0

Combine like terms: -2i + -2i = -4i
-1(4 + -4i + 1i2) = 0
(4 * -1 + -4i * -1 + 1i2 * -1) = 0
(-4 + 4i + -1i2) = 0

Solving
-4 + 4i + -1i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(-2 + i)(2 + -1i) = 0

Subproblem 1
Set the factor '(-2 + i)' equal to zero and attempt to solve:

Simplifying
-2 + i = 0

Solving
-2 + i = 0

Move all terms containing i to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + i = 0 + 2

Combine like terms: -2 + 2 = 0
0 + i = 0 + 2
i = 0 + 2

Combine like terms: 0 + 2 = 2
i = 2

Simplifying
i = 2
Subproblem 2
Set the factor '(2 + -1i)' equal to zero and attempt to solve:

Simplifying
2 + -1i = 0

Solving
2 + -1i = 0

Move all terms containing i to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1i = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1i = 0 + -2
-1i = 0 + -2

Combine like terms: 0 + -2 = -2
-1i = -2

Divide each side by '-1'.
i = 2

Simplifying
i = 2
Solution
i = {2, 2}