-(2/3)(3x-4)+3x=(5/6)

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Solution for -(2/3)(3x-4)+3x=(5/6) equation: 



-(2/3)(3x-4)+3x=(5/6)

We move all terms to the left:

-(2/3)(3x-4)+3x-((5/6))=0



Domain of the equation: 3)(3x-4)!=0

x∈R



We add all the numbers together, and all the variables

-(+2/3)(3x-4)+3x-((+5/6))=0

We add all the numbers together, and all the variables

3x-(+2/3)(3x-4)-((+5/6))=0

We multiply parentheses ..

-(+6x^2+2/3*-4)+3x-((+5/6))=0

We calculate fractions


(-6x^2)/()+3x+()/()=0

We add all the numbers together, and all the variables

(-6x^2)/()+3x+1=0

We multiply all the terms by the denominator


(-6x^2)+3x*()+1*()=0

We add all the numbers together, and all the variables

(-6x^2)+3x*()=0

We get rid of parentheses

-6x^2+3x*()=0

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