-(2/3)(4x-5)=6

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Solution for -(2/3)(4x-5)=6 equation:



-(2/3)(4x-5)=6
We move all terms to the left:
-(2/3)(4x-5)-(6)=0
Domain of the equation: 3)(4x-5)!=0
x∈R
We add all the numbers together, and all the variables
-(+2/3)(4x-5)-6=0
We multiply parentheses ..
-(+8x^2+2/3*-5)-6=0
We multiply all the terms by the denominator
-(+8x^2+2-6*3*-5)=0
We get rid of parentheses
-8x^2-2+5+6*3*=0
We add all the numbers together, and all the variables
-8x^2=0
a = -8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-8)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-16}=0$

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