-(2/3)(y+12)+(2/3y)=-(5/4y)+2

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Solution for -(2/3)(y+12)+(2/3y)=-(5/4y)+2 equation: 



-(2/3)(y+12)+(2/3y)=-(5/4y)+2

We move all terms to the left:

-(2/3)(y+12)+(2/3y)-(-(5/4y)+2)=0



Domain of the equation: 3)(y+12)!=0

y∈R





Domain of the equation: 3y)!=0

y!=0/1

y!=0

y∈R





Domain of the equation: 4y)+2)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

-(+2/3)(y+12)+(+2/3y)-(-(+5/4y)+2)=0

We get rid of parentheses

-(+2/3)(y+12)+2/3y-(-(+5/4y)+2)=0

We multiply parentheses ..

-(+2y^2+2/3*12)+2/3y-(-(+5/4y)+2)=0

We calculate fractions

We do not support eypression: y^3

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