-(2/3)*(x-3)-x=8

Solution for -(2/3)*(x-3)-x=8 equation:

-(2/3)(x-3)-x=8

We move all terms to the left:

-(2/3)(x-3)-x-(8)=0


Domain of the equation: 3)(x-3)!=0

x∈R


We add all the numbers together, and all the variables

-(+2/3)(x-3)-x-8=0

We add all the numbers together, and all the variables

-1x-(+2/3)(x-3)-8=0

We multiply parentheses ..

-(+2x^2+2/3*-3)-1x-8=0

We multiply all the terms by the denominator


-(+2x^2+2-1x*3*-3)-8*3*-3)=0

We add all the numbers together, and all the variables

-(+2x^2+2-1x*3*-3)=0

We get rid of parentheses

-2x^2+1x*3*-2+3=0

We add all the numbers together, and all the variables

-2x^2+1x*3*+1=0

Wy multiply elements

-2x^2+3x^2+1=0

We add all the numbers together, and all the variables

x^2+1=0

a = 1; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·1·1
Δ = -4
Delta is less than zero, so there is no solution for the equation